233A - Perfect Permutation - CodeForces Solution


implementation math *800

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Python Code:

n = int(input())
lst = [0] * n
if n % 2 != 0:
    print("-1")
else:
    for i in range(0, n):
        if i % 2 == 0:
            lst[i+1] = i + 1
        else:
            lst[i-1] = i + 1
    finLst = [str(x) for x in lst]
    print(" ".join(finLst))






C++ Code:

#include <bits/stdc++.h>

using namespace std;
int main()
{
    int n;
    cin >> n;
    int a[n];
    for (int i = 1; i <= n; i++)
    {
        a[i] = i;
    }
    if (n % 2 != 0)
        cout << "-1" << endl;
    else
    {
        for (int i = 1; i <= n-1; i += 2)
        {
            swap(a[i], a[i+1]);
        }
        for (int i = 1; i <= n; i++)
        {
            cout << a[i] << " ";
        }
    }

    return 0;
}


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